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leetcode/array/1binary search/35search-insert-position/python/solution.py
flowerstonezl e1006fa09c first init
2026-01-29 17:04:05 +08:00

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"""
LeetCode 解题模板
使用方法:
1. 在 Solution 类中实现你的算法
2. 在 if __name__ == "__main__" 中添加测试用例
3. 运行python solution.py
"""
from typing import List
class Solution:
"""
示例:搜索插入位置
给定一个排序数组和一个目标值,在数组中找到目标值,并返回其索引。
如果目标值不存在于数组中,返回它将会被按顺序插入的位置。
请必须使用时间复杂度为 O(log n) 的算法。
"""
def searchInsert(self, nums: List[int], target: int) -> int:
"""
搜索插入位置
Args:
nums: 排序数组
target: 目标值
Returns:
目标值的索引,如果不存在则返回插入位置
"""
left, right = 0, len(nums) - 1
while left <= right:
mid = left + (right - left) // 2
if nums[mid] == target:
return mid
elif nums[mid] < target:
left = mid + 1
else:
right = mid - 1
return left
def print_test_result(test_name: str, passed: bool):
"""打印测试结果"""
status = "✓ 通过" if passed else "✗ 失败"
print(f"{test_name}: {status}")
def assert_equals(actual: int, expected: int) -> bool:
"""比较两个整数是否相等"""
return actual == expected
if __name__ == "__main__":
solution = Solution()
# 测试用例 1: 目标值存在于数组中
nums1 = [1, 3, 5, 6]
target1 = 5
result1 = solution.searchInsert(nums1, target1)
expected1 = 2
print_test_result("测试用例 1: 目标值存在", assert_equals(result1, expected1))
# 测试用例 2: 目标值不存在,应插入到中间位置
nums2 = [1, 3, 5, 6]
target2 = 2
result2 = solution.searchInsert(nums2, target2)
expected2 = 1
print_test_result("测试用例 2: 插入中间位置", assert_equals(result2, expected2))
# 测试用例 3: 目标值大于所有元素
nums3 = [1, 3, 5, 6]
target3 = 7
result3 = solution.searchInsert(nums3, target3)
expected3 = 4
print_test_result("测试用例 3: 插入末尾", assert_equals(result3, expected3))
# 测试用例 4: 目标值小于所有元素
nums4 = [1, 3, 5, 6]
target4 = 0
result4 = solution.searchInsert(nums4, target4)
expected4 = 0
print_test_result("测试用例 4: 插入开头", assert_equals(result4, expected4))
print("\n所有测试完成!")